CODI PER CONVERTIR UN KNOB DE 12 PASSOS AMB SORTIDA DE 12 PASSOS DEFINITS PER L'USUARI
Incloure el seguit fórmules de més a baix en un mòdul Formula Controller.
+inter(a,P1,P2)*S
Del Pas P2 fins P2 del Knob, el valor de sortida será S
+inter(a,0.000,0.083)*0.40
+inter(a,0.084,0.167)*0.07
+inter(a,0.168,0.250)*0.53
+inter(a,0.251,0.333)*0.20
+inter(a,0.334,0.417)*0.67
+inter(a,0.418,0.500)*0.33
+inter(a,0.501,0.583)*0
+inter(a,0.584,0.667)*0.47
+inter(a,0.668,0.750)*0.13
+inter(a,0.751,0.833)*0.60
+inter(a,0.834,0.917)*0.27
+inter(a,0.918,1)*0.73
Una altra solució al problema anterior però amb mòduls individuals posats en sèrie:
Case(ifGE(a,0)+ifL(a,1/12),a,((1/15)*6)/10)
Case(ifGE(a,1/12)+ifL(a,(1/12)*2),a,((1/15))/10)
Case(ifGE(a,(1/12)*2)+ifL(a,(1/12)*3),a,((1/15)*8)/10)
Case(ifGE(a,(1/12)*3)+ifL(a,(1/12)*4),a,((1/15)*3)/10)
Case(ifGE(a,(1/12)*4)+ifL(a,(1/12)*5),a,((1/15)*10)/10)
Case(ifGE(a,(1/12)*5)+ifL(a,(1/12)*6),a,((1/15)*5)/10)
Case(ifGE(a,(1/12)*6)+ifL(a,(1/12)*7),a,0)
Case(ifGE(a,(1/12)*7)+ifL(a,(1/12)*8),a,((1/15)*7)/10)
Case(ifGE(a,(1/12)*8)+ifL(a,(1/12)*9),a,((1/15)*2)/10)
Case(ifGE(a,(1/12)*9)+ifL(a,(1/12)*10),a,((1/15)*9)/10)
Case(ifGE(a,(1/12)*10)+ifL(a,(1/12)*11),a,((1/15)*4)/10)
Case(ifGE(a,(1/12)*11)+ifL(a,(1/12)*13),a,((1/15)*11)/10)